If a2+ b2 = 80 and ab = 32, then find the value of 1/a + 1/b
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a2 + b2 = 80 and ab = 32
(a + b)2 = a2 + b2 + 2ab = 80 + 2 × 32 = 80 + 64 = 144
⇒ a + b = 12
(a – b)2 = a2 + b2 – 2ab = 80 – 2 × 32 = 80 – 64 = 16
⇒ a – b = 4
a-b = 4 = 1 = 0.333
a+b 12 3
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