if a2+b2=89 and a-b =3,find the value of
1.ab
2.a+b
3.(a2-b2)
please don't ignore this question
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Answer:a2 + b2 = 10
ab = 13
a2+b2 = (a+b)2 -2ab
10 = (a+b)2 - 2 × 13
10 = (a+b)2 - 26
-(a+b)2 = -26 -10
-(a+b)2 = -36
(a+b) = √36
a+b = 6
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