Math, asked by ajaymaggo7, 7 months ago

if a2+b2=89 and a-b =3,find the value of
1.ab
2.a+b
3.(a2-b2)
please don't ignore this question ​

Answers

Answered by itsbiswaa
14

Answer:a2 + b2 = 10

ab = 13

a2+b2 = (a+b)2 -2ab

10 = (a+b)2 - 2 × 13

10 = (a+b)2 - 26

-(a+b)2 = -26 -10

-(a+b)2 = -36

(a+b) = √36

a+b = 6

Step-by-step explanation:

Answered by chetananand48
0

Answer:

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