if a²+b²=9 and ab=4 find the value of 3(a+b)²-2(a-b)²
Answers
Answered by
48
(a+b)²=a²+b²+2ab
=9+2(4)
=17
(a-b)²=a²+b²-2ab
=9-2(4)
=1
3(a+b)²-2(a-b)²=3(17)-2(1)
=61-2
=59
=9+2(4)
=17
(a-b)²=a²+b²-2ab
=9-2(4)
=1
3(a+b)²-2(a-b)²=3(17)-2(1)
=61-2
=59
aiman7:
no its wrong ans
Answered by
54
a²+b²=9
ab=4
3(a+b)²-2(a-b)²
3(a²+b²+2.a.b)-2(a²+b²-2.a.b)
3(9+2×4)-2(9-2×4)
3(9+8)-2(9-8)
3(17)-2(1)
51-2
49:ans
ab=4
3(a+b)²-2(a-b)²
3(a²+b²+2.a.b)-2(a²+b²-2.a.b)
3(9+2×4)-2(9-2×4)
3(9+8)-2(9-8)
3(17)-2(1)
51-2
49:ans
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