If a²+b²=9 and ab=4 find the value of 3(a+b)²-2(a-b)²
Answers
Answered by
3
(a+b)²=a²+b²+2ab= 9+2*4=17
(a-b)²=a²+b²-2ab=9-2*4=1
putting both values in eq.
3*17-2*1=49
(a-b)²=a²+b²-2ab=9-2*4=1
putting both values in eq.
3*17-2*1=49
Answered by
3
Step-by-step explanation:
a ²+ b² =9
ab= 4
(a+b)²=a²+b²+2.a.b
=> 9+2×4
=>17
(a-b)² = a²+b²-2.a.b
=> 9-2×4
=> 1
3(a+b)² - 2(a-b)²
=>3×17 - 2×1
=>51 - 2
=> 49
Hope this is helpful to U ✨
Similar questions