If a²+b²+c²=0, then find the value of 2a+3b–4c.
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The squares of numbers are always non- negative. If any of the squares was greater than one the sum would be greater than zero.
This implies that all three squares are equal to zero.
This means that a = b = c = 0.
The value of 2a+3b-4c will be zero too.
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