Question

if a²+b²+c²=125 and ab+bc+can=50, find a+b+c​

Answer 1

Answer:

a²+b²+c²=125

Formula: (a+b+c​)²= a²+b²+c²+2(ab+bc+ca)

(a+b+c)²-2(ab+bc+ca)=125

(a+b+c)²-2(50)=125

a+b+c=√225

a+b+c=15

Answer 2

Given a²+b²+c²=125 and ab+bc+ca=50

(a+b+c​)²= a²+b²+c² + 2(ab+bc+ca)

(a+b+c​)² = 125 + 2(50) = 125 +100 = 225

(a+b+c) = 15

Mark as brainliest if it helped:D