Question

If a² + b² + c² = 132 and ab + bc + ca = 6, find a + b + c *
1 point
16
14
10
12
​

Answer 1

Step-by-step explanation:

(a+b+C)²=a²+b²+c²+2ab+2bc+2ca

Now put the given values

(a+b+C)²=(132)+[2(6)]

(a+b+c)²=132+12

(a+b+c)²=144

{on taking square root}

a+b+c=✓144

a+b+c= ±12