If a2+b2+c2=16 and ab+bc+ca=10, find the value of a+b+c.
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Answered by
238
Hii there!!!
( a + b + c )^2 = a^2 + b^2 + c^2 + 2( ab + bc + ca )
=> ( a + b + c )^2 = 16 + 2×10
=> ( a + b + c )^2 = 36
=> a + b + c = Root 36 = 6
Hope it helps....
( a + b + c )^2 = a^2 + b^2 + c^2 + 2( ab + bc + ca )
=> ( a + b + c )^2 = 16 + 2×10
=> ( a + b + c )^2 = 36
=> a + b + c = Root 36 = 6
Hope it helps....
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Answered by
58
(a+b+c)^2-(2a+2b+2c)=a^2+b^2+c^2
(a+b+c)^2_2.10=16
a+b+c =6
(a+b+c)^2_2.10=16
a+b+c =6
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