Question

If a2 + b2 + c2 = 16 and ab+bc+ca = 10, find the value of a3+b3+c3 – 3abc.
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Answer 1

Answer:

A2+b2+ C2=16

(a+b+c)2=16

a+b+c=4

and ab+bc+ca=10

We know, A3+b3+C3= (a+b+c)(A2+b2+c2-ab-bc-ca)

=4(16-10)

4×6=24

hence the answer is 24

Step-by-step explanation:

he the value of A2+b2+c3 is given from that is got the value of a+b+c after that I put the value in (a+b+c)(A2+b2+c2-ab-bc-ca) the formula of A3+b3+c3-3abc and I got the answer

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