Question

If a²+b²+c² = 250 and ab+bc+ca =3, then find a+b+c​

Answer 1

Answer:

Step-by-step (a+b+c)² =a²+b²+c²+2ab+2bc+2ca

(a+b+c)² =a²+b²+c²+2(ab+bc+ca)

Put the value of a²+b²+c² and ab+bc+ca which is given in the question then

(a+b+c)²= 250+2*3

(a+b+c)²= 256

then , a+b+c= (256)½

Hence a+b+c= 16

Since 16 is the square root of 256.

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Answer 2

Answer:

Step-by-step explanation:

±16 is the answer

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