Question

if a2+b2+c2=280 and ab+bc+ca=3 find a+b+c

Answer 1

Answer:

Step-by-step explanation:

Given:

a²+b²+c²=280

ab+bc+ca=3

To find:a+b+c

Solution:

(a+b+c)²=a²+b²+c²+2(ab+bc+ca)

(a+b+c)²=280+2(3)

(a+b+c)²=280+6

a+b+c=√286

a+b+c=16.911(approx)

Answer 2

Answer:16.911(approx)

Step-by-step explanation:

(a+b+c)^2=(a^2+b^2+c^2)+2ab+2bc+2ac

(a+b+c)^2=280+2(ab+bc+ac)

(a+b+c)^2=280+2(3)

(a+b+c)^2=280+6

(a+b+c)^2=286

a+b+c= square root of 286

a+b+c=16.911(approx)