Question

If a²+b²+c²=280 and ab+bc+can=9/2 then find the value of (a+b+c)³

Answer 1

Step-by-step explanation:

(a+b+c)^2= a^2+b^2+c^2+2 (ab+bc+ca)

putting the values given in the question

(a+b+c)^2=280+2*9/2=289

a+b+c= 17

Now, (a+b+c)^3= 17^3=4913

Answer 2

Answer:

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