If a²+b²+c²=29,and ab+BC+CA=26, find the value of a+b+c
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using identity - (a+b+c)2 = a2+b2+c2 + 2ab+2bc+2ca
we get :-
(a+b+c)2 = a2+b2+c2 + 2(ab+bc+ca)
(9)2 = a2+b2+c2+2(23)
81=a2+b2+c2+52
81-52=a2+b2+c2
29=a2+b2+c2
we get :-
(a+b+c)2 = a2+b2+c2 + 2(ab+bc+ca)
(9)2 = a2+b2+c2+2(23)
81=a2+b2+c2+52
81-52=a2+b2+c2
29=a2+b2+c2
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@Sanskriti141
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Please refer to the attachment for the solution....
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#BE BRAINLY
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Sanskriti141:
thanks!
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