Math, asked by sdft988, 1 year ago

If a²+b²+c²=29,and ab+BC+CA=26, find the value of a+b+c

Answers

Answered by ravi34287
4
using identity - (a+b+c)2 = a2+b2+c2 + 2ab+2bc+2ca

we get :-

(a+b+c)2 = a2+b2+c2 + 2(ab+bc+ca)

(9)2 = a2+b2+c2+2(23)

81=a2+b2+c2+52

81-52=a2+b2+c2

29=a2+b2+c2

Answered by Sanskriti141
38
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