Question

If a2+b2+c2=49 and ab+bc+ca=36 , find a+b+c=

Answer 1

$\star\:\:\:\sf\large\underline\blue{Answer:-}$

Given,

$\sf {a}^{2} + {b}^{2} + {c}^{2} = 49$

$\sf ab + bc + ac = 36$

Therefore,

$\sf a + b + c$

$\sf = \sqrt{ {a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ac)}$

$\sf = \sqrt{49 + 72}$

$\sf = \sqrt{121}$

$\sf = \pm11$

Answer 2

Answer:

HOPE IT HELPS BUDDY...