If a2 + b2 + c2 = 6 and a + b + c = 20, then the value of (ab + bc + ca) is
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Step-by-step explanation:
(a+b+c)² = a²+b²+c²+2(ac+bc+ca)
(20)² = 6+2(ab+bc+ca)
400 = 6+ 2(ab+bc+ca)
400-6 =2(ab+bc+ca)
394 = 2(ab+bc+ca)
∴ ab+bc+ca = 197
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