Math, asked by yumi61, 1 year ago

if a2+b2+c2=80 and a+b+c =20, find ab. +bc.+ ca​

Answers

Answered by swastikmittal
2

Answer:

not possible

Step-by-step explanation:

2a+2b+2c=80

2(a+b+c)=80

a+b+c=40

but you said that

a+b+c=20

and

20≠40

Answered by myna51
20

Step-by-step explanation:

a+b+c=20

squaring on both sides

(a+b+c)2=(20)2

a2+b2+c2+2ab+2bc+2ca=400

a2+b2+c2+2(ab+bc+ca)= 400

80+2(ab+bc+ca)=400

2(ab+bc+ca)=400-80

2(ab+bc+ca)=320

ab+bc+ca=320÷2

ab+bc+ca=160.

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