if a2+b2+c2=80 and a+b+c =20, find ab. +bc.+ ca
Answers
Answered by
2
Answer:
not possible
Step-by-step explanation:
2a+2b+2c=80
2(a+b+c)=80
a+b+c=40
but you said that
a+b+c=20
and
20≠40
Answered by
20
Step-by-step explanation:
a+b+c=20
squaring on both sides
(a+b+c)2=(20)2
a2+b2+c2+2ab+2bc+2ca=400
a2+b2+c2+2(ab+bc+ca)= 400
80+2(ab+bc+ca)=400
2(ab+bc+ca)=400-80
2(ab+bc+ca)=320
ab+bc+ca=320÷2
ab+bc+ca=160.
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