If a² + b² + c² = 8r² then prove that the triangle is right angle
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If ABC is right angled, then by Pythagoras law, then a^2 + b^2 = c^2. So, since a constant 8R^2 is present in the equation, it is not a right angled triangle.
Please verify.
Here we may take
2c^2 = 8R^2
so c^2 = 4R^2
so c = 2R.
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