if a2 +b2+c2-ab-bc-ca=0 when a=b=c
Answers
Answered by
0
Answer:
what do we have to do????
Answered by
2
Answer:
a^2+b^2+c^2-ab-bc-ca=0
multiply both sides with 2,we get
2(a^2+b^2+c^2-ab-bc-ca)=0
2a^2+2b^2+2c^2-2ab-2bc-2ca=0
(a^2-2ab+b^2)+(b^2-2bc+c^2)+(c^2-2ca+a^2)
(a-b)^2+(b-c)^2+(c-a)^2=0
Since the sum of square is zero then each term should be zero
(a-b)^2=0,(b-c)^2=0,(c-a)^2=0
(a-b)=0,(b-c)=0,(c-a)=0
a=b, b=c, c=a
Hence a=b=c.
proved#
☆▪▪▪▪▪▪Thank you▪▪▪▪▪▪☆
Similar questions