if a2+b2+c2=ab+bc+ca,then the value of a3+b3+c3 is
Answers
Answered by
1
Answer:
∵ a
3
+ b
3
+ c
3
- 3abc
= (a
2
+ b
2
+ c
2
- ab - bc - ca)(a + b + c)
= a
2
+ b
2
+ c
2
= ab + bc + ca (given)
⇒ (a
2
+ b
2
+ c
2
- ab - bc - ca) = 0
∴ a
3
+ b
3
+ c
3
- 3abc
(a + b + c) x 0 = 0
∴ a
3
+ b
3
+ c
3
= 3abc
Similar questions