if a²+b²+c²=(b+c-1). then find the value of a+b+c
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(a+b+c)²=a²+b²+c²+2(ab+bc+ ca) Here, (a+b+c)² will be 0 for any real value of a, b and c => a²+b²+c²+2(ab+bc+ca) = 0
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- yes above answer is correct it will be zero only
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