if a²+b²=c² show that 1/log b+c a+1/log c-b a=2
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Answer: B) 2
Explanation:
Given a2 + b2 = c2
Now 1logc+a(b) + 1logc−a(b)
= log b(c+a) + log b(c−a)
= log b(c2−a2)
= 2logb(b) = 2
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