Question

if a² + b² is not equal to zero then prove that a is not equal to zero and b is not equal to zero​

Answer 1

Answer:

= (a+b) (a-b)

Explanation:

when the numbers taken in that place find it.

Answer 2

Answer: here it is

Explanation:

if a not=0 ;

a^2 not=0;

if a~=0;

a^2 >0;

if b not=0;

b^2 not=0;

if b~not=0;

b^2>0;

so for a^2+b^2 = 0;

a not=0; and b not=0;

OR

a^2+b^2 is not =0 ,then we know ( a+b)^2 =a^2+b^2+2ab .

So a^2+b^2 = (a+b)^2 - 2ab.

So (a+b)^2–2ab not=0 from above 2 equations.

Now (a+b)^2 ≥ 2ab always.

And the equation suggests that (a+b)^2 =2ab .and this will be possible only three cases are possible (a,b)=(1,1)or (-1,-1)or (0,0).

Therfore but since when (a,b)=(1,1)or (-1,-1),then a^2+b^2 ≠0.

So (a,b)is not=(0,0).

hope it helps you