Question

If a2(square)-5a-1=0 then a-1\a=?​

Answer 1

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${a}^{2} - 5a - 1 = 0$

Answer 2

Step-by-step explanation:

a² - 5a - 1 = 0

A = 1, B = -5, C = -1

a = (-B ±√B²-4AC)/2A

a = (-(-5) ± √(-5)² - 4(1)(-1))/2(1)

a = (5 ± √25 + 4)/2

a = (5 ± √29)/2

a = (5 + √29)/2 and (5 - √29)/2

a - 1/a = (a² - 1)/a

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