If a2sec2 θ - b2tan 2 θ = c2,
Prove that sin θ = PLUSMINUS Whole root of c2 - a2 / c2 - b2
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First we will put the value of sec^2Q in the given equation.
Then we will get the value of tan^2Q.
Then we can find the value of sec^2Q and also the value of cosQ.
Then as we know, sinQ is equal to tanQ.cosQ, we can find the value of sinQ
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Answer:
+/- (root) c^2-a^2/(root) c^2-b^2
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