Math, asked by abhinavvirat8633, 1 year ago

If a2sec2x - b2tan2x = c2 then the value of sec2x + tan2x is equal to (assume b2 ≠ a2 )

A) b2-a2+2c2b2+a2 B) b2+a2-2c2b2-a2 C) b2-a2-2c2b2+a2 D) b2-a2b2+a2+2c2

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Answered by Anonymous

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D is the answer mate.......

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