Math, asked by bansalvarun6094, 1 year ago

If a3 + 3a2 + 9a = 1, then what is the value of a3 + (3/a)?

Answers

Answered by hitjoshi1996
0
(x+1)(x+2)=(x+1)(x+2)=(x)(x)+(x)(2)+(1)(x)+(1)(2)=x2+2x+x+2=x2+3x+2
Answered by virtuematane
1

Answer:

The value of the expression:

a^3+\dfrac{3}{a}=28

Step-by-step explanation:

We are given the expression as:

a^3+3a^2+9a=1

Now on taking 'a' common we get:

a(a^2+3a+9)=1\\\\a^2+3a+9=\dfrac{1}{a}

( since on dividing both side by a)

\dfrac{3}{a}=3\times (a^2+3a+9)\\\\\\\dfrac{3}{a}=3a^2+9a+27\\\\a^3+\dfrac{3}{a}=a^3+3a^2+9a+27\\\\\\a^3+\dfrac{3}{a}=1+27

( since using the value of the original expression)

a^3+\dfrac{3}{a}=1+27=28

Hence, the value of the expression:

a^3+\dfrac{3}{a}=28

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