Math, asked by manandarak4655, 10 months ago

If a3 - b3 = 208 and a b = 4, then (a + b)2 ab is equal to:

Answers

Answered by 27mannat
0

Answer:

4(3)-4(3)=7 and4+4(2)(33) =32*33 ans hope it helps

Answered by harendrachoubay
1

The value of (a+b)^2 - ab is equal to 52.

Step-by-step explanation:

The question is:

If a^3 - b^3 = 208 and a - b = 4, then (a + b)^2 - ab is equal to:

We have,

a^3-b^3=208 and a - b = 4

To find, the value of (a+b)^2 - ab = ?

(a+b)^2 - ab

= a^2+b^2+2ab - ab

= a^2+b^2+ab

Using the algebraic identity,

a^3-b^3=(a-b)(a^2+b^2+ab)

Put a^3-b^3=208 and a - b = 4, we get

208=(4)(a^2+b^2+ab)

a^2+b^2+ab =\dfrac{208}{4}

a^2+b^2+ab = 52

∴ The value of (a+b)^2 - ab = 52

Thus, the value of (a+b)^2 - ab is equal to 52.

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