If a3 + b3 = 35 and ab = 6, then what is the value of a + b?
A) 5 B) 8 C) 2 D) -8
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The answer is A.5
Step-by-step explanation:
we know that-
a³+b³=(a+b)(a²-ab+b²)
35= (a+b)(-ab+(a+b)²-2ab)
[using identity: (a+b)²=a²+b²+2ab]
35=(a+b)(-3ab+(a+b)²)
35=(a+b)(-3×6+(a+b)²)
35=(a+b)(-18+(a+b)²)
35= -18(a+b)+(a+b)³
Put a + b = x
⇒ x3 – 18x – 35 = 0
Using trial error method,
(Trick: Put values of x as given in the options)
Putting x = 5
L.H.S. = 125 – 90 – 35 = 0 = R.H.S.
∴ a + b = 5
Hope it helps!
(pls mark it the brainliest^^)
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