If a³+ b³ + c³ = 3abc and (a + b + c) is not equal to 0 then-
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Step-by-step explanation:
the question must be:
if a³+b³+c³=3abc and a+b+C is not equal to zero then a²+b²+c² is equal to zero.
I think
for this question the answer is
a ³+b³+c³=3abc
using the identity,
x cube plus y cube plus z cube = (a plus b plus c)(a² plus b² plus c²-ab-bc-ac)+3xyz
likewise,
(a plus b plus c ) (a² plus b² plus c²) plus 3abc=3abc(gn)
3abc got cancelled on both the sides,
(a plus b plus c ) (a² plus b² plus c²-ab-bc-ac) =0
using identity,
a² plus b² plus c²= (a plus b plus c)(a² plus b² plus c²-ab-ac-bc)
a² plus b² plus c²=0
hence proved.
hope it helps
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