Question

if a3+b3+c3=3abc, then a+b+c=? (where a,b,c are not equal.)

Answer 1

Statement 2:a + b + c = 0(a + b + c)^3 = a^3 + b^3 + c^3 + (3ab +3bc + 3ca) (a + b + c) – 3abcSubstitute for a + b + c = 0 in the above equation:0 = a^3 + b^3 + c^3 - 3abc=> 3abc = a^3 + b^3 + c^3=> (a^3 + b^3 + c^3)/abc = 3