if a3+b3+c3=3abc then the value of a+b+c where a not equal to b and c
Answers
Answered by
28
Hi ,
*********************************************
We know the algebraic identity ,
x³ + y³ + z³
= (x+y+z)(x²+y²+z²-xy-yz-zx) + 3xyz
*************************************
Now ,
a³ + b³ + c³ = 3abc ( given )
(a+b+c)(a²+b²+c²-ab-bc-ca)+3abc=3abc
(a + b + c)(a²+b²+c² - ab - bc - ca) = 0
a + b + c = 0
Or
a² + b² + c² - ab - bc - ca = 0
Required condition is ,
a + b + c = 0
Where ,
a ≠ b and a ≠ c
I hope this helps you.
: )
*********************************************
We know the algebraic identity ,
x³ + y³ + z³
= (x+y+z)(x²+y²+z²-xy-yz-zx) + 3xyz
*************************************
Now ,
a³ + b³ + c³ = 3abc ( given )
(a+b+c)(a²+b²+c²-ab-bc-ca)+3abc=3abc
(a + b + c)(a²+b²+c² - ab - bc - ca) = 0
a + b + c = 0
Or
a² + b² + c² - ab - bc - ca = 0
Required condition is ,
a + b + c = 0
Where ,
a ≠ b and a ≠ c
I hope this helps you.
: )
Answered by
12
Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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