if a³+b³+c³=3abc then what's the value of a+b+c(note:a≠b≠c)
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Step-by-step explanation:
if a³+b³+c³=3abc then what's the value of a+b+c(note:a≠b≠c)=0
because
we know that
a³+b³+c³-3abc = (a+b+c)(a^2+b^2+c^2-ab-cb-ca)
a³+b³+c³-3abc = (0)(a^2+b^2+c^2-ab-cb-ca)
a³+b³+c³-3abc = 0
a³+b³+c³=3abc --------------proved
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