Math, asked by kcbflk, 11 months ago

if a³+b³+c³=3abc then what's the value of a+b+c(note:a≠b≠c)​

Answers

Answered by sonalithakur82
1

Answer:

0

Step-by-step explanation:

if a³+b³+c³=3abc then what's the value of a+b+c(note:a≠b≠c)​=0

because

we know that

a³+b³+c³-3abc = (a+b+c)(a^2+b^2+c^2-ab-cb-ca)

a³+b³+c³-3abc = (0)(a^2+b^2+c^2-ab-cb-ca)

a³+b³+c³-3abc = 0

a³+b³+c³=3abc  --------------proved

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