if a4+b4=14a2+b2, then let us show that log a2+b2=log a +log b +2log 2
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Step-by-step explanation:
Given a
2
+b
2
=14a
2
b
2
or, (a+b)
2
=16a
2
b
2
Now taking logarithm both sides with respect to the base e we get,
2log(a+b)=log16+loga
2
+logb
2
or, 2log(a+b)=4log2+2loga+2logb
or, log(a+b)=2log2+loga+logb>
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