if a4+b4= 14a2b2 show that,loge(a2+b2)=logea+logeb+2loge2
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(a^2+b^2)^2-2a^2b^2=14a^2.b^2
(a^2+b^2)^2=16a^2.b^2
now take loge both side
=>loge (a^2+b^2)^2=loge (16a^2b^2)
=> 2loge(a^2+b^2)=4loge2+2loge a+2loge b
=> loge (a^2+b^2)=2loge2+loge a+loge b
(a^2+b^2)^2=16a^2.b^2
now take loge both side
=>loge (a^2+b^2)^2=loge (16a^2b^2)
=> 2loge(a^2+b^2)=4loge2+2loge a+2loge b
=> loge (a^2+b^2)=2loge2+loge a+loge b
abhi178:
please mark as brainliest
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