If AABB is crossed to aabb and the F1 is test crossed. What % of the test cross progeny will be aabb itth
genes are
P. Unlinked?
Q. Completely linked (no crossing over at all)?
R. 10 map units apart?
S. 24 map units apart?
a. P-0%, Q - 0%, R - 38%, S - 45%
b. P - 25%, Q - 50%, R - 45%, 5 - 38%
C. P-0%, Q - 25%, R - 45%, S - 38%
d. P - 25%, Q- 0%, R - 38%, S - 45%
Answers
Answer:
Explanation:
c will be the answer
p. if unlinked all progeny will be AaBb
q. if completely linked they will be in the ratio 1:2:1
r. 10 map units equivalent to 10% recombinant formation than rest be 90% and its half will 45%aabb
s. similar to above calculation 38% recombinant rest 76% and half of 76% is 38%
Answer:
(b) part is correct
Explanation:
Parents: AaBb and aabb
P. Since they are unlinked, independent assortment will take place and 50% of progeny will be parental where as 50% will be recombinants. So, 25% AaBb +25% aabb
.
Q Complete linkage means that no recombinants will be obtained so 100% of progeny will be Parental I. e 50% AaBb +50% aabb
R. 10 map units is equals to 10% recombination frequency which means that 90% parental,so 45% AaBb + 45% aabb.
S. Same as R, 24 map units apart means 24% recombination frequency, that means 76% parental and half of this will be aabb.