Question

If aand alpha beta are the zero of x2-5x+4 then find a*alpha beta

Answer 1

Given equation

$x^{2} -5x+4=0$

Solving, we get,

$x^{2} -5x+4=0$

$\implies x^{2} -4x-x+4=0$

$\implies x(x-4)-1(x-4)=0$

$\implies (x-1)(x-4)=0$

Now,

$x-1=0\\\implies \boxed{\boxed{\bold{x=1}}}}}}}}}$

$x-4=0\\\implies \boxed{\boxed{\bold{x=4}}}}}$

                                                         

Answer 2

Answer:

α=1,β=4

Step-by-step explanation:

x2-5x+4⇒-4*-1=4,-4-1=-5

x2-4x-x+4

x(x-4)-1(x-4)

(x-1)(x-4)

α=x-1=0

α=1

β=x-4=0

β=4