If aand b are the 4th and 8th multiple of 3 and 7 respectively then the sum of their succesive multiple is
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Step-by-step explanation:
1st multiple of 3 = a/4
1st multiple of 7 = b/7
sum of successive multiple
= (a/4+b/7) + 2(a/4+b/7) +3(a/4+b/7)+......
.......n(a/4+b/7)
= (a/4+b/7) ( 1+2+3+4+...........+n)
= (a/4+b/7) ( n) ( n+1) /2
=> n(n+1) (a/4+b/7) /2
This is the answer
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