if Aand B are two events such that P(A)=0.16,P(B)=0.24 and P(A and B)=0.11,then the probability of obtaining only one of the two events is?
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Narain007:
please anyone try this sum and send me solution soon
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P(AUB) =P(A) +P(B) -P(AIntersection B)
0.11=0.24+0.16 -P
P = 0.29
hope it helps!!
0.11=0.24+0.16 -P
P = 0.29
hope it helps!!
sorry i appreciate you for solving but the answer is 0.18
if u get solution for this answer send me
then P(A and B) means A intersection B
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