Question

If
AB = 12 cm , BC = 16 cm and AB is perpendicular
to BC, then the radius of the circle passing
through the points A, B and C is​

Answer 1

Answer:

C

10 cm

Given- A,B & C are points such that AB=12cm and BC=16cm and BC⊥AB.

To find out- the radius of the circle passing through A,B & C=?

Solution- BC⊥AB i.e ∠ABC=90

0

and ΔABC is a right one with AC as hypotenuse. ∴AC=

AB

2

+BC

2

=

12

2

+16

2

cm=20cm. So the circle passing through A,B & C will have its diameter as AC.

∴ Its radius=

2

1

×20cm=10cm.

Step-by-step explanation:

plz make my ans as brainliest

Answer 2

Answer:

the answer is 10cm

apply Pythagoras theorem.

${ac}^{2} = {12}^{2} + {16}^{2}$

ac=20cm

ac/2=10cm