Question

if AB =12 cm,BC =16cm and AB is perpendicular BC ,then what is the radius of the circle passing through the points A,B and C?​

Answer 1

Explanation:

draw the bisector of ab and bc the point at which the bisector meet that is the centre of circle and take the pencil needle to b point then make the circle this is the required circle

Answer 2

The radius of circle is 10 cm

Explanation:

ABC is a triangle.

where AB = 12 cm and BC = 16 cm

AB is perpendicular to BC. So, AC is hypotenuse of triangle ABC.

A circle passing though points A, B and C.

ABC is right angle triangle.

It means triangle ABC inscribed in a circle.

So, Hypotenuse of ABC is diameter of circle.

$AC^2=AB^2+BC^2$

$AC^2=12^2+16^2$

$AC=\sqrt{400}$

$AC=20$

The diameter of a circle is 20 cm

Radius is half of diameter.

Radius = 10 cm

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