Question

if AB= 12 cm BC= 16cm and AB is perpendicular to BC, then the radius of the circle passing through the point A,B and C is​

Answer 1

ANSWER:

10cm

EXPLANATION:

Given:

AB = 12 cm,

BC = 16 cm

AB ⊥ BC

Method used : Pythagoras Theorem,

{ Hypotenuse² = Perpendicular² + Base²}

⇒ AC² = AB² + BC²

⇒ AC² = 12² + 16²

⇒ AC² = 144 + 256

⇒ AC² = 400  

⇒ AC = √400

AC = 20 cm

Hypotenuse = AC = 2r

r = AC/2

r = 20/2

∴Radius = 10 cm