if AB=12cm, BC=16CM AND AB IS perpendicular to BC, then radius of circle passing through the points A , B and C is
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Answered by
3
The centre of the circumcircle of a right angle triangle lies on the mid point of its hypotenuse of the triangle. So, use Pythagorean theorem to find AC. Finally radius will be AC/2, i.e., 10
Answered by
7
ANSWER:
10cm
EXPLANATION:
Given:
AB = 12 cm,
BC = 16 cm
AB ⊥ BC
Method used : Pythagoras Theorem,
{ Hypotenuse² = Perpendicular² + Base²}
⇒ AC² = AB² + BC²
⇒ AC² = 12² + 16²
⇒ AC² = 144 + 256
⇒ AC² = 400
⇒ AC = √400
AC = 20 cm
Hypotenuse = AC = 2r
r = AC/2
r = 20/2
∴Radius = 10 cm
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