Question

If AB=12cm, BC=16cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is???​

Answer 1

Answer:

Given- A,B & C are points such that AB=12cm and BC=16cm and BC⊥AB.

To find out- the radius of the circle passing through A,B & C=?

Solution- BC⊥AB i.e ∠ABC=90

0

and ΔABC is a right one with AC as hypotenuse. ∴AC=

AB

2

+BC

2

=

12

2

+16

2

cm=20cm. So the circle passing through A,B & C will have its diameter as AC.

∴ Its radius=

2

1

×20cm=10cm.

Answer 2

Answer:

radius = 10 cm

Step-by-step explanation:

Let's start by writing the given values.

AB = 12 cm

BC = 16 cm, also states that they are perpendicular

radius is unknown

We could use the Pythagorean Theorem to solve this problem. Recall c² = a² + b²

Let AB = a, BC = b, and radius = c.

c² = 12² + 16²

√c² = √400

c = 20

So the circle passing through A,B & C will have its diameter as AC.

Then radius = 1/2 x 20, which is equal to 10 cm.

Hope it helps.