If ab=12cm bc=16cm and ab perpendicular bc then radius of circle
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Answered by
3
Answer:
abc.is a rt. Led triangle
ab=I2, bc=I6
hypotenuse ac =v12^2+I6^2 =v4oo=20
. Here radius is half of the hypoten use 20/2=lOcm
Answered by
2
ANSWER:
10cm
EXPLANATION:
Given:
AB = 12 cm,
BC = 16 cm
AB ⊥ BC
Method used: Pythagoras Theorem,
⇒ AC² = AB² + BC²
⇒ AC² = 12² + 16²
⇒ AC² = 144 + 256
⇒ AC² = 400
⇒ AC = √400
AC = 20 cm
Hypotenuse = AC = 2r
r = AC/2
r = 20/2
∴Radius = 10 cm
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