Question

If ab=12cm bc=16cm and ab perpendicular bc then radius of circle

Answer 1

Answer:

abc.is a rt. Led triangle

ab=I2, bc=I6

hypotenuse ac =v12^2+I6^2 =v4oo=20

. Here radius is half of the hypoten use 20/2=lOcm

Answer 2

ANSWER:

10cm

EXPLANATION:

Given:

AB = 12 cm,

BC = 16 cm

AB ⊥ BC

Method used: Pythagoras Theorem,

⇒ AC² = AB² + BC²

⇒ AC² = 12² + 16²

⇒ AC² = 144 + 256

⇒ AC² = 400  

⇒ AC = √400

AC = 20 cm

Hypotenuse = AC = 2r

r = AC/2

r = 20/2

∴Radius = 10 cm