If AB ^2 + BC ^2 =290cm^2,
AM=8cm,find BC. Figure is sent down
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Answer:
Step-by-step explanation:
In ∆ABC
AM is the median
BM=MC
AB^2+BC^2=290
AM=8 , BC=?
By apollinius Therom
AB^2+BC^2=2AM^2+2BM^2
290=2×(8)^2+2BM^2
290=2×64+2BM^2
290=128+2BM^2
290-128=2BM^2
162=2BM^2
162/2=BM^2
81=BM^2
Taking square root
BM=9
BM=MC
MC=9
B-M-C
BC=BM+MC
=9+9
BC=18
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