If ab=2,bc=6 and ca=3 then find the value of a solve
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First we see, ab=2 which implies to b=2/a…..(i)
Now bc=6; putting the val. of ‘b’ from (i) we get, 2/a ×c=6…..=> c=3a..
So, ca=6. Then, 3a^2=6..now a=1
So the answer is a= 1
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