Question

If ab = 24, bc = 24, ac = 16 find :
(i) a + b + c
(ii) a² + b^2+ c^2+ 2(ab + bc + ac).

Answer 1

ab=24, bc=24,ac= 16

or,a=24/b,c=24/b,a=16/c

comparing,

24/b=16/c

16c=24b

c=24b/16

=3b/2

again comparing,

3b/2=24/b

3b sq.=48

b sq. =16

b=4

new solve the other value

Answer 2

ab=bc=24

so a=c

from ac=16

a*a=16

a^2=16

so a=4

a=c=4

b=6

a+b+c=14

4²+6²+4²+2(4+6+4)=96