if AB=2AC find BC And plz plz plz plz plz plz plz plz plz plz plz say the answer
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In right triangle ADC, angle ADC = 90°,
angle CAD = 60°
tan(CAD) = tan60° = CD/AD
√3 = CD/100
CD = 100√3 ... (i)
Now,
In right triangle ADB, angle ADB = 90°,
angle BAD = 60°
cot(BAD) = cot60° = AD/BD
1/√3 = 100/BD
BD = 100√3 ... (ii)
BC = CD + BD = 100√3 + 100√3 = 200√3
Hence, BC = 200√3 m.
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