If AB = 2x + 3, BC = 3x - 5, and AC = 38, what is the value of x?
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If A, B, and C lie on the same line; AB = 2x + 3, BC = 3x - 5, and AC = 38, then what is the value of x?
Given:
AB = 2x + 3,
BC = 3x - 5,
AC = 38
To find:
The value of x
Solution:
IF the given points lie on the same line so it must follow;
the rule which stated as:
AB+BC = AC
- 2x+3+3x-5 = 38
- 5x-2 = 38
- 5x = 40
- x = 40/5
- x = 8
So the value of the x is 8
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