If AB = 3sin.x + 4cos.x, State the maximum length of AB and the value of x for which this occurs
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Answer:
maxm length of AB is 5
occurs at x=arcsin(3/5)
Step-by-step explanation:
u can multiply divide by 5
then take 3/5as cos y
so 4/5 =sin y
so AB =5[sinXcosY+cosXsinY]
AB=5sin(sinX+Y)
ABmax=5
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