Question

If AB = 3sin.x + 4cos.x, State the maximum length of AB and the value of x for which this occurs

Answer 1

Answer:

maxm length of AB is 5

occurs at x=arcsin(3/5)

Step-by-step explanation:

u can multiply divide by 5

then take 3/5as cos y

so 4/5 =sin y

so AB =5[sinXcosY+cosXsinY]

AB=5sin(sinX+Y)

ABmax=5